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ssm A person in a kayak starts paddling, and it accelerates from 0 to 0.60 m/s in a distance of 0.41 m. If the combined mass of the person and the kayak is 73 kg, what is the magnitude of the net force acting on the kayak?

32$N$

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in this question, the person is handling a Qaida and by doing that it goes from a speed off zero meters per second to 0.6 meters per second in a spatial inter haul off 0.41 meters. We have to to know what is the magnitude of the net force that is acting on a kayak. The magnitude of the net force after next is equal. Stupid mask off the kayaks times acceleration of the car we know what is the mass. It's standing treat. So the net force is equals two, 73 times the acceleration. Now how can you discovered acceleration knows that we don't know what is the time interval that it takes for the chi active ill from the zero to be equals to 0.6. But no one is the spatial interval so we can use to retaliate equation To solve this question started charges equation is as follows. The square is because the initial velocity squared two crimes declaration kinds of displacement. Therefore, the final velocity is 0.6 and squared and it goes to the initial velocity which is equal to zero. So you just zero then we have you on the next term, which is true kinds. The acceleration Times X placement off 0.4 to 1. Then we can sew for declaration by standing this term on this term to the other side dividing. So we have that explanation is your question 0.6 square divided by true Pines Euro Coin 41 And this is a question. 0.36 divided by zero corn 82. Then week. Unplugging these acceleration the equation for the net force. And then we get that the net force is egos, too. 73 times 0.36 divided by 0.8 troops and this results in the net force off approximately 32 noodles.

Brazilian Center for Research in Physics