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SSM A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.870 m/s at an angle of 35.0 above the table, and it lands on the magazine 0.0770 s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

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Video Transcript

So the question states a bug jumps on top of a magazine. Ah, with speed, with initial speed of 0.870 meters per second, an angle of 35 degrees with the total flight time of 350.770 seconds and we need to find the height of this magazine. So to do this, all we really need to focus on is the vertical components of the velocity, the horizontal proponents, me nothing. We're just trying to find the vertical displacement of the spider. So to find V of X r v of why we can do the falling. So we know that sign of 35 degrees is equal to be of why, over 0.870 meters per second, so we can solve for via boy which is equal to point for 99 meters per second. Now that we know what via why is we can substitute this into our kingdom attics, formula which states that the Delta X is equal to the velocity times time plus 1/2 a T squared. We know what the velocity is, which is just point for 99 meters per second. We know what the time is and we also know what the acceleration is. It's just the acceleration due to gravity which is negative nine point heat meters per second squared and so we can sub everything in into this formula and sulfur Delta X. And when we do this, we find that the height of the magazine is 0.937 meters, which is also same thing as 9.37 millimeters.

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John D. Cutnell, Kenneth W. Johnson

Physics

Elyse Gonzalez

Marshall Styczinski

Aspen Fenzl

Meghan Miholics

This textbook answer is only visible when subscribed! Please subscribe to view the answer

Physics

Elyse Gonzalez

Marshall Styczinski

Aspen Fenzl

Meghan Miholics

John D. Cutnell, Kenneth W. JohnsonPhysics

Elyse Gonzalez

Marshall Styczinski

Aspen Fenzl

Meghan Miholics

John D. Cutnell, Kenneth W. Johnson

Physics