00:01
Okay, let's begin this problem by looking at a top -down view of the ground, or at least a rectangular or portion of it.
00:12
In this view, directly up will be towards the north, directly down towards the south.
00:18
To the right would be east, and to the left would be west.
00:24
Now, we're given that the horizontal component of the magnetic field is headed directly to the north, and we know that a proton, which we represent here as a dot with charge plus e, is headed directly to the east at some velocity v.
00:47
We're given that the speed of this proton is such that the magnetic force that the proton feels is equal and opposite to the weight that the proton feels due to gravity.
01:01
If we use the right -hand rule, we see that the magnetic force is directed out of the screen or directly up and we'll represent that as a dot with a circle around it and of course the gravitational force is going to be headed directly downward because it's going to go towards the ground and that is represented as a vector with a it's an x with a circle around it now because we know that they're balanced we know that the magnitudes of these forces are also balanced so we can say that the magnitude of the magnetic force is equal to the magnitude of the gravitational force, of course, acting on this project.
01:48
From the textbook, the magnitude of the magnetic force is given by the charge of the particle, multiplied by its speed, multiplied by the magnitude of the magnetic field through which the particle is traveling, and then lastly, multiplied by the sign of the angle between the magnetic field vector and the velocity vector of the object we care about.
02:08
Be equal to the gravitational force of this on this object and that is just the mass of that object or the proton multiplied by the acceleration due to gravity.
02:16
The question asked what speed allows for this balance? that means we want to solve for the variable v and we're going to do that now...