💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here!

Like

Report

Get the answer to your homework problem.

Try Numerade Free for 7 Days

ssm The sun is more massive than the moon, but the sun is farther from the earth. Which one exerts a greater gravitational force on a person standing on the earth? Give your answer by determining the ratio $F_{\operatorname{sun}} / F_{\operatorname{mon}}$ of the magnitudes of the gravitational forces. Use the data on the inside of the front cover.

178

Physics 101 Mechanics

Chapter 4

Forces and Newton’s Laws of Motion

Newton's Laws of Motion

Applying Newton's Laws

University of Washington

Simon Fraser University

University of Winnipeg

Lectures

04:16

In mathematics, a proof is…

04:48

In mathematics, algebra is…

02:25

(a) What is the magnitude …

03:17

What is the ratio of the g…

06:44

Determine the gravitationa…

05:34

How does the gravitational…

05:59

00:43

Is the size of the gravita…

01:37

What is the ratio of the s…

12:27

The gravitational force at…

00:49

Is the force that the Sun …

00:28

Why do both the Sun and th…

in this question, we have to couple into the following reshoot the magnitude of the gravitational force exerted on the earth by the sun, divided by the magnitude of the gravitational force exerted on the earth by the moon. Remember that the magnitude of the gravitational force is given by the Newtown constant times the mass off the object one in this case, the mass of the Sun Times the mass of the earth divided by the distance between the earth and the sun squared on the denominator. We have the magnitude off the gravitational force exerted by the moon. And this is given by the Newton constant times the mass off the moon times the mass off the earth divided by the distance between here and the moon squared So note that there will be a lot of simplifications here Nearly is equals to g times And as times m e divided by r. P s squared times r e m squared divided by G and m times m e. So these are simply fired and the masses off the earth are also simply fired. So we got r e m squared divided by R E s squared times m s divided by M m. As the result off the ratio between the magnitudes off the rotational forces. Then they plug in the values that were given by the problem we got the following the ratio is it goes to 3.85 time stand to eat, squared, divided by 1.5 I'm stand 11. It's weird times the mass off the sun 1.99 times 10 to the 30 divided by the mass of the moon 7.35 times Stand in the 22 and these givers approximately 170 feet. So the gravitational force exerted on the earth by the sun is 178 times bigger than the gravitational force exerted on the earth by the moon.

Numerade Educator

In mathematics, a proof is a sequence of statements given to explain how a c…

In mathematics, algebra is one of the broad parts of mathematics, together w…

(a) What is the magnitude of the gravitational force that the Earth exerts o…

What is the ratio of the gravitational pull of the sun on the moon to that o…

Determine the gravitational force that (a) the Sun exerts on the Moon, (b) E…

How does the gravitational force exerted by Earth on the sun compare with th…

Is the size of the gravitational force that Earth exerts on the Moon smaller…

What is the ratio of the sun's gravitational force on the moon to the e…

The gravitational force at different places on Earth due to the Sun and the …

Is the force that the Sun exerts on Earth bigger, smaller, or the same size …

Why do both the Sun and the Moon exert a greater gravitational force on one …