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Starting at $\mathrm{A},$ an ideal gas undergoes a cyclic process involving expansion and compression, as shown here. Calculate the total work done. Does your result support the notion that work is not a state function?

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$-101 \cdot 3 J$

Chemistry 101

Chapter 6

Thermochemistry

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Lectures

05:27

In chemistry, a chemical reaction is a process that leads to the transformation of one set of chemical substances to another. Both reactants and products are involved in the chemical reactions.

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In chemistry, energy is what is required to bring about a chemical reaction. The total energy of a system is the sum of the potential energy of its constituent particles and the kinetic energy of these particles. Chemical energy, also called bond energy, is the potential energy stored in the chemical bonds of a substance. Chemical energy is released when a bond is broken during chemical reactions.

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Consider the following cyc…

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An ideal gas expands at a …

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An ideal gas at a given st…

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So for this problem, we have some gas that undergo since stages and we're supposed to find the toilet work done. So for here we have gas from a and it goes to B to C to d and then all the way back to a So it's a cyclic process. So the way we're going to do this is we're gonna find the work done from A to B B to C. C to D and detailed Add those all together to find total work that is done. So the equation that we're going to use throughout all this for gases that work equals negative pressure times change in volume. Let's first look at eight to be all sorts easy because change in volume zero, which means there's constant volume and the work is also zero. As you can look from the equation now from B to C. So in this case, the pressure is to a t M. And we can find the change in the volume because the final volume at sea it's two years in the initial value might be is one leader. When you multiply those two together, you will get the work is negative two leaders times a. Then we go from C to D. It's the exact same as from A to B, because a change in volume zero which means that the work done is also zero. Lastly, we go from the A and from need A. It's similar to B to C because now the pressure this time is 1 p.m. We know that the final volume at A is one year. We know that the volume ideas two years. When you multiply those together, you'll get the work done. Is he positive? One teacher a GM. So total work will just be the sum of all of these combined, which is negative two plus one, which means that it is negative One leader times HTM So that is a total work that is done. And you can also convert this to Jules. And we know that because there is 101.3 jewels for every leader a. T m. That also means that negative 101 0.3 jewels of work done. So we know from this example that work cannot be a state function because in a state function, the only thing that matter is the beginning of the end point. And from here, the beginning of the end point are the exact same. We started a and ended A, which means that it should be zero, because we didn't go anywhere the beginning of the end of the same. But yet ah, work is still a non zero value when it's negative. One leader times a team which proves that it is path dependent and that work is not a state function, so it does support that notion.

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