Question
Starting from rest, a particle moving in a straight line has an acceleration of $a=(2 t-6) \mathrm{m} / \mathrm{s}^{2},$ where $t$ is in seconds. What is the particle's velocity when $t=6 \mathrm{s}$, and what is its position when $t=11$ s?
Step 1
We know that acceleration is the derivative of velocity with respect to time, so we can write this as $\frac{dv}{dt} = 2t - 6$. Show more…
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Starting from rest, a particle moving in a straight line has an acceleration of a = (2t - 6) m/s^2, where t is in seconds. What is the particle’s velocity when t = 6 s, and what is its position when t = 11 s?
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