00:01
For this problem, we need to find the dual problem related to the minimization equation given to us here.
00:08
W equals y -sup 1 plus y -sub -2 plus 4 -y -sub -3 with the constraints as shown.
00:16
Now, what does it mean to find the dual problem for this particular exercise? well, duality says that there is a connection between standard minimization and standard maximization problems.
00:29
Specifically, duality says that any solution of a standard maximization problem produces the solution of an associated standard minimization problem.
00:39
And these problems we call duels of each other.
00:43
So what is that associated maximization problem that goes along with this minimization problem? well, to find that, i'm first going to create an augmented matrix that's going to capture all of the information in this minimization problem.
00:57
I'm going to start with my constraints.
01:03
I'm going to put all of the coefficients and constants into this matrix.
01:06
So the first row, if i look at those coefficients, those coefficients, i have one, two, three, and the constant is 115.
01:17
So that'll be my first row.
01:19
Second constraint will give me my second row.
01:21
Those coefficients are 2, 1, 8, and 200.
01:26
Third row, 1 ,0, 1.
01:29
You have no y sub 2s, so we're just going to put a zero there.
01:33
So 1 ,0, 1, and 50.
01:35
And i'm going to finish with my minimization row.
01:39
I'm not going to make these negative like we do with the simplex method.
01:42
I'm just going to put down the coefficients.
01:45
So that is 1, 1, and 4.
01:50
Now we're going to transpose this matrix.
01:54
Transposing means that the rows become columns and the columns become rows.
01:58
So first row, 1, 2, 3, 115.
02:03
1, 2, 3, 115.
02:07
That first row is now my first column.
02:11
Row 2 becomes column 2 .1 -8 -200.
02:17
2 -1 -200.
02:21
Row 3 becomes column 3, 1 -0 -150, 1 -0 -150...