00:01
Statement 1 is given that we have b plus c plus a plus a plus b is in hp, then b plus c over a c over b, a plus a of c is in hb.
00:08
And statement 2 is if each term was equal in gp is squared, regarding cetus is a gp.
00:13
Work on the statement 2.
00:15
If we take a gp, that's given as a, a r square, a r2, and so on.
00:23
If a square each terms, we get a square, a square r square, a square r to the part 4, a square r126.
00:31
But you can see it is still in gp right because the commentation is coming out to be r square.
00:37
This is in gp.
00:38
So statement 2 is correct.
00:39
We work on statement 1, we want that b plus t plus a plus b is in hp.
00:44
That means 1 over b plus t 1 over c plus a 1 over a plus b is in ap...