00:01
Hi, the first we look at a statement two here.
00:06
Statement two says that, portion number 174, if a1, 823 are in ap, then a1 plus k, a2 plus k, 3 plus k was an ap.
00:18
That's a property of ap, we know that.
00:19
So statement two is, now we look at statement one, a, b, c are in ap, then b plus c negative a, b plus c negative a, c plus a negative b, c plus a negative b, and then we have a plus b negative c, a plus b negative c, in ap.
00:45
So we assume that it's an ap.
00:47
We assume that it's an ap, which is multiplied by negative 1, all the terms.
00:51
So it will be a negative b, negative c, then b negative c negative a, then c negative a, negative a, negative a negative b, it will be in ap, right? that will be in ap.
01:02
Now we add a plus b plus c to all the terms.
01:05
We can do that...