Question
Statement-1: Let $f(x)=\frac{20}{4 x^{3}-9 x^{2}+6 x}$ then therange $f=[6,20]$Statement-2: $\int$ increases on $(1 / 2,1)$ and decreases on $(1, \infty) \cup(-\infty, 1 / 2)$.
Step 1
We have the function \( f(x) = \frac{20}{4x^3 - 9x^2 + 6x} \). To find the range of \( f \), we first need to determine the behavior of the denominator \( 4x^3 - 9x^2 + 6x \). Show more…
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Monotonocity
Level II
As shown.
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