Question
Statement 1 $\mathrm{S}_{r}$ is the sum of an infinite $\mathrm{G} . \mathrm{P}$ with 1st term $\mathrm{r}$ and common ratio $\frac{1}{\mathrm{r}+1}$. Then $\mathrm{S}_{\mathrm{r}}-\mathrm{r}$ depends on $\mathrm{r}$. andStatement 2 Sum of an infinite geometric series the common ratio is numerically less than 1 exists only if $\div \mathrm{r} \div<1$
Step 1
The sum of an infinite geometric series with common ratio r exists only if $|r|<1$. This is a well-known fact in mathematics. The sum of an infinite geometric series is given by $\frac{a}{1-r}$, where a is the first term and r is the common ratio. This formula is Show more…
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Statement 1 The sum of any number of terms from the beginning of the series $1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\ldots \ldots \ldots$, cannot exceed $2 .$ and Statement 2 The sum to infinity of a GP whose first term is a and common ratio is $r$ where, $|r|<1$ is finite and is equal to $\frac{a}{1-r}$.
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