00:01
And this problem, we have a two -stage turbine, where we have steam coming in for the first stage.
00:09
And then coming out of the first stage, we actually split the line.
00:13
And they say for other uses, we take 10 % of the mass of steam coming out of the first stage and we use it for other things.
00:24
And then 90 % of it, we feed back into the second stage.
00:29
And then that comes out there.
00:31
And so obviously these are connected.
00:34
And it's very much similar to the tap we had in the first thing, where we just, you could think of that problem, not in the first thing.
00:40
In another problem we had a, we said we had a tap in here or a bleed line.
00:46
This is kind of like a bleed line, basically, but if you just look at this whole thing as one turbine, it's kind of like a bleed line coming out here.
00:55
So anyway, we have, then the rest of this, 90 % of it going into the same.
01:00
Second stage and then coming out.
01:02
Coming in, we have 7 megapascals and 400 degrees c.
01:08
This is a mass ratio.
01:09
So the mass flow out at 2 here is 10 % of what's coming in here.
01:18
And then the mass flow that goes through here winds up at 3 and into here is 0 .9 times the mass flow rate of here.
01:28
We're told that both stages have an is centropic efficiency of 88%.
01:33
We're also told that the pressure coming out of the first stage is 1 .8 megapascals.
01:40
So if we make a control volume around both these stages here, and again, it's running a steady state so we can use the entropy and figure out the entropy balance, entropy generated.
01:53
So the rate of entropy generation is the rate of entropy flowing out at three, the rate of entropy flowing out at two, and minus the rate of entropy flowing out at two, and minus the rate of entropy flowing out.
02:04
Of entropy flowing in at 1.
02:06
And again, substituting these relationships for the mass flow rates, we get that this is, you know, m .t times 0 .9 times the entropy at this specific entropy here, plus 0 .1 times the specific entropy here, and minus the specific entropy at 1.
02:25
And again, once we know this, we can find the exigy destroyed.
02:29
And i guess they gave us the surrounding temperature, was, what did they have at 25? if i had to do you see, there we come.
02:41
So we need to find these guys.
02:46
Well, at one, that one's easy because we have two thermodynamic properties.
02:50
So we can get the entropy and the entropy there.
02:55
Now, we know the efficiencies.
02:59
So in the isentropic case, the entropy at two would be the entropy at 1, which would give us the iscentropics.
03:08
Anthropic enthalpy at 2, because we'll take pressure at 2 and then the isotropic enthalpy.
03:15
And so we get the isotropic entropy at 2.
03:21
Now because we know the efficiency and we know how the efficiency relates to the enthopies, the real and then the isotropic case, we can then solve for the actual enthalpy at 2.
03:34
And that turns out to be 2 ,870, about 2 ,871 kilojoules per kilogram.
03:43
And now that we know the actual enthalpy at 2, and we know the pressure at 2, we can get the entropy at 2...