00:01
So here on this question, we can use the formula for heat transfer by convection.
00:05
So q, convection is equal to h -a, t -s -minus -t -infinity, where q, convection is the heat transfer rate, as is the heat transfer coefficient, a is the surface area, t is the surface temperature, and t -infinity is the surrounding temperature.
00:24
Now, for a 1 -meter length of a tube, the surface area without the fins, is a is equal to pi d into l.
00:31
Where desired to diameter and l is the length of the tube now in this case d is equal to 0 .05 meters l is equal to 1 meter so area a is 5 into 0 .05 into 1 and that is 0 .157 meters square now we can find the heat transfer rate without the fins so q convection without or we say no fins, no, pins, and that is equal to ha, t, s minus t, infinity, and that is 40 into 0 .157 into 180 minus 25, and this comes out to be 133 .4 watts.
01:21
Now we need to find the heat transfer rate with the fins, so the total area with pins can be calculated as a total, and that is the a plus n where a fin where n is the number of fins per meter written a is the fin the total surface area and we found out as a fin is equal to pi d out minus d in into l where d out is the outer diameter d in is the inner diameter and l is the length of the fin and from here plugging in the values so a fin is equal to pi into 0 .06 minus 0 .05 into 0 .003.
02:07
And this comes out to be 0 .000942 meter square.
02:13
Now we can find the total surface area of the pins...