00:01
So for this question, we need to set out the energy balance equation here, which is e .9 equal e.
00:05
And if we expand it, we have qdin plus mdah1 is equal mdah2.
00:09
Qdi here is the rate of a heat transfer to the cooling water.
00:15
And mdi here is the mass flow rate for the cooling water.
00:20
And the h1 here is the initial entropy for the cooling water.
00:30
And h2 here is the final entropy for the cooling water.
00:35
If we do some arrangement here, we have q -dion is equal to m -dha -t times h2 minus h1, which is equal to m -dhawn 10 -cp2 minus t1.
00:42
Cp is a specific heat and constant pressure for the water and t2 is the final temperature for the cooling water and t1 is the initial temperature for the cooling water.
00:51
And we also know that the rate of heat transfer into the cooling water can be equal to the rate of a condensation of the sting in the condenser multiplied by the heat of vaporization.
01:03
According to energy conservation law.
01:06
Because when the rate of heat transferred to the cooling water, that means that these things also losing the heat from itself, since it's transferring to the cooling water.
01:17
So now we can use...
01:21
Actually, this one should be condensation.
01:24
So m .d.
01:25
Condensation...