00:01
So in this question, the effect of varying the percent excess air during the steady flow combustion, steady for combustion flow has to be seen here and steady flow of hydrogen is to be studied here.
00:19
So when we analyze the thing, the combustion equation of hydrogen with stoichiometric amount of air is h2 plus 0 .50 plus 3 .76 into the stockometric amount, which gives you h2 plus 0 .0 plus 0 .76 into.
00:48
This is the shockometric amount.
00:55
Now, for the incomplete combustion, so this is our first thing.
01:05
For incomplete combustion, with 100 % excess air.
01:13
The combustion equation of the above equation comes to be like this.
01:26
1 plus x .6 .02 plus 3 .76n2 gives you 0 .97 h2 plus a .h2 plus a .h2 plus b02.
01:50
Plus c n2 so this is there for the incomplete combustion now the coefficients these coefficients have to be determined right from the mass balances now for hydrogen balance we have 2 equals to 0 .97 into 2 plus 2 8 where we get a to be 0 .03 now oxygen balance is 1 plus 6 .03 now oxygen balance is 1 plus x x into 0 .5 into 2 that is equals to 0 .97 plus or 2b can write b into 2 okay so and now the nitrogen balance we have to see nitrogen into balance is 1 plus x into 0 .5 into 3 .76 into 2 is 1 plus x into 0 .7 6 into 3 .76 into 2 is to c into two.
03:00
So these are the different balances that we have.
03:03
So solving the equations we find the coefficients we have x is equals to 1...