00:01
So for this problem, i have that special phrase that the amount has a rate of change, so dadt, that is proportional to the amount present.
00:12
So when you are given this differential equation, you should know that that solves into a equals the initial amount times e to the kt.
00:24
So you can solve this whole differential equation by separating the variables and integrating both.
00:30
Sides and then solving.
00:32
But if you have this particular special differential equation, then you can just memorize that it turns into this.
00:38
Now, we are told that we are given eight grams, and then that decays into four grams.
00:46
So our amount is four after you take the initial amount of eight, and that decays in three point, i'm sorry, that decays in three hours.
00:59
So our t is three.
01:01
And then to solve for our k, i can divide both sides by 8, so that's one half equals e to the 3k...