00:01
So in this problem, we have the system of two equations, and we're going to solve it using the method of substitution.
00:07
So we actually already have both equations solved for y.
00:10
So we can substitute either way.
00:13
Let's take this one where y is solved for and substitute it in for y into the second equation.
00:20
So when we do that, we will get x squared equals x plus 12.
00:25
Since this is a quadratic to solve it, we generally want it set equal to zero.
00:30
So to make a that happen, we'll subtract x and subtract 12th through the other side.
00:37
Oops, minus, so minus x, minus 12.
00:43
Now this is ready to factor, and this factors into x minus 4, and x plus 3 equals 0.
00:52
So from this, we get two solutions for x...
