Suggest mechanisms for the following electrophilic addition reactions. (Section 21.3)

Answer

Related Courses

Organic Chemistry

$Book Cover for Chemistry $^{3}$ : …$

Chemistry $^{3}$ : Introducing inorganic, organic and physical chemistry

Chapter 21

Alkenes and alkynes: electrophilic addition and pericyclic reactions

Discussion

You must be signed in to discuss.

Top Organic Chemistry Educators

Watch More Solved Questions in Chapter 21

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Video Transcript

so rest to give the products in the following reactions. In the first one, we have propane or to make a Peruvian. So the in implying we have in our keen and then counting from this carpet, we've won two. So two methyl parathion. Mm hmm. Reacting with HCL. So the Al Keen is going to act as the nuclear file or a Louis base. Great Britain And the chlorine is gonna get birth electrons in this bond because it's a lot more luxury negative and the carbon capture and is going to form here because we have more substitue its surrounding it. We have this method, this one and this one. So the more substituted Carver cast iron is the more stable at us and sub substituted meaning the more are groups that has, or alcohol, alcohol groups, carbon groups. The last step is for the chlorine to attack it. So we get two methyl to corporate pain. Next one is three metal butin with HBR. So you get a similar reaction. Yeah, Keen's a nuclear fall bringing its both electrons. So notice this carbon has more substitue. It's than in this carbon right here. This carbon has two metals one and two. This one only has this method. So therefore what's gonna happen is something called a hydraulic shift. The hydrogen on this carbon is going to move over here and the carbon Catalan is going to live where hydrogen was. So if it's tertiary carbon cast iron well, except for bringing to attack it, Should we get to metal to Bergamo? Routine X one is metal cycle vaccine. So cyclo implying with the ring Hexi into six reacting with again hbr but this time over peroxide. So whenever you react HBR or HCL over peroxide, you're gonna get the formation of a less substituted carpet. Karen, it's gonna forum here instead of right here because this is a secondary carbon cat on and this is fresh air. So in the beginning, it's the same same step there a keen attacks or grabs Britain and by step is for women to attack the carbon count on. So you get super air yet one bromo, two methods cycle vaccine and we also have what is called a Cairo center. So this carbon is bound to four different groups. There's the hydrogen right here. So that's two already 12 And then this side is different than this side. So on this side we have a ch two ch two verse on the side. We have a Revis ch ch three or C h Yes, h three. So we have carbon, carbon, hydrogen, hydrogen. But we have a second hydrogen here and the carbon here and carbon has a a, um, higher atomic number than the hydrogen. So does my more priority. So as a result, this side over here is going to be number two. This is three. By default, the borough means one, because as the highest atomic number, the hydrogen is 42 going from 3 to 1 and then from wanted to ignoring, for we have the s. So assuming that the broom is on the wedge, control the Carl centers. So you bring me in on the wedge. As a result, Hodgins on the dash, and then So these are known as an answer MERS room in then the hydrogen, their hydrogen so against S and the star. And the last one is going to be European with Vallarta. So whenever you react, dialogues stand as high hydrogen. Eric, Hey, origination over methanol and we're gonna get anti edition. So this Al Keen draws electron density away from this brimming and focuses it that way. So this brew mean is more susceptible to nuclear Filic attack from the alkaline. So to tax it green means go over the electrons go over there we have this intermediate bring me in methods on the dash Draw that. And then the last step is for the Birmingham was expelled and the first step to attack from the back and breaking this this ring structure. So as a result, we get anti edition of the the highlights shall be so. This is on the dash. This is on the wedge and we have the metal right here. So you get that. Okay. Mhm. We'd all the Carol center right here because we only this method is the same as this method. Over here we have two method has been all four different groups. Let's keep that in mind.

Get More Help with this Textbook

$Book Cover for Chemistry $^{3}$ : …$