Question
Sum to $n$ terms of the series$1+\frac{1}{1+2}+\frac{1}{1+2+3}+\ldots$, is(A) $\frac{n}{n+1}$(B) $\frac{2 n}{n+1}$(C) $\frac{n}{n-1}$(D) None of these
Step 1
We can simplify this by using the formula for the sum of the first n natural numbers, which is $\frac{n(n+1)}{2}$. So, the nth term becomes $\frac{2}{n(n+1)}$. Show more…
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