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Superman throws a 2400 -N boulder at an adversary. What horizontal force must Superman apply to the boulder to give it a horizontal acceleration of 12.0 $\mathrm{m} / \mathrm{s}^{2} ?$
2940 $\mathrm{N}$
Physics 101 Mechanics
Chapter 4
Newton's Laws of Motion
Physics Basics
Motion Along a Straight Line
Motion in 2d or 3d
Cornell University
Rutgers, The State University of New Jersey
University of Michigan - Ann Arbor
McMaster University
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right here. We're supposed to You figure out how much how hard Superman must pushed to make the boulder. Sorry. 12 meters per second squared people. I am Newton's second law. We know the some of the forces on X is equal to the mass times acceleration on X and you don't have to worry about you mean form of vertical. For certain things were just doing this horizontal throw. We can actually only one force being put on it. And that's him throwing it so me. To simplify this equation to just the force on X equals the mass times acceleration of X. We want the exhilaration 12 meters per second squared. So we really want force the next equal mass times 12 use per second squared the weight of the older has 2400 Newtons, which is really same as 2400 kilograms times meters per second squared so we can divide the weight in Newtons by 9.8 muse per second squared so gravity to obtain its mass and kilograms. So major second squares to bite out about kilograms and 20 100 divided by 9.8 a cheat looking, my scratch work. Okay, 244.9. And so we have that. The force hopes yeah, that the force is equal to 244.9. Oops, that's right. Two and 44.9 times 12 kilograms as meters per second squared, which is equal to a grand total of probably we should see a rental grounding approximately 2900 and 40 Nunes and we're done.
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