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Supermassive black holes are thought to exist at the center of many galaxies.(a) What is the radius of such an object if it has a mass of $10^{9}$ suns?(b) What is this radius in light years?
a. $2.95 \times 10^{12} \mathrm{m}$b. $3.12 \times 10^{-4} \mathrm{ly}$
Physics 103
Chapter 34
Frontiers of Physics
Wave Optics
Particle Physics
University of Michigan - Ann Arbor
University of Washington
Simon Fraser University
University of Winnipeg
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right. So the first part of this problem is to calculate the social medias from a black hole whose masses tend to the nine times the mass off our son. So here is the relation off Social Radius, which is to GM over C Square. We'll just plug in the values here so two times u turn's constant, which is this and then the mass of the black hole. Just change the nine times the mass of the sun, divided by speed off light square which is three times 10 to 8 meters per second squared. Now When you sold this, you will get the result to be 2.95 times 10 to the 12 meters. A pretty big number now. The second part of the problem is to convert this into like Hughes now one like you contains how many meters it contains. 9.46 times tend to the 15 meters. Now we multiplied this with the radius that we obtained. Excuse me in the first part and we get the radius in light years to be 3.12 times 10 to the minus four light years. So just using this relation, we first opt in the radius and then we converted the radius. Two light years
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