00:01
All right, in this question, we're talking about supernova, in particular, supernova in 1987a.
00:07
And the first question asks us when did it occur.
00:12
All right, so you know that light travels at the speed of light, and the light reached us in 1987, which is an astronomical terms basically now.
00:23
So its distance in light years is going to be equal to the amount of years ago that it happened.
00:32
Distance to this star is 1 .68 times 10 to the 5 light years.
00:42
So therefore, t time ago before present at which it happened is equal to 1 .68 times 10 to the 5 years.
00:54
All right, simple enough.
00:56
Now question b says that some protons were launched at the time of a supernova with 100 giga electron volts of kinetic energy and we want to know at what time do these protons reach the earth so i'm going to call this um t arrival okay so the time which they arrive is going to be the same thing as the time it takes for the protons to travel to earth um minus the time of arrival or the minus the amount of time that takes the light to arrive added to 1987 okay so we need to figure out the velocity of the protons in order to figure out what or how long it should take the protons to arrive so we can find velocity from energy normally we use the formula k -e is equal to one -half and b squared.
02:06
But this is for non -relativistic velocities.
02:08
This formula will not work for very high velocities like you have after supernova.
02:14
So instead, we have to use a different formula, which is that kinetic energy is equal to m, which in this case is the massive proton, times c squared, times the quantity of 1 over the square root of 1 minus v squared over c squared, and then minus 1 close quantity.
02:38
All right, so in order to solve the velocity, we have to do several steps of algebra.
02:43
We can start by dividing this stuff off to the other side.
02:47
So we'll have ke over mpc squared is equal to 1 over the square root of 1 minus v squared over c squared, and then minus 1.
03:02
Now we can add one to the other side, multiply this term up, divide this term down, so that's going to give us v is equal to, so i'm doing a lot of steps at once, but hopefully you can follow the algebra.
03:17
1 minus the quantity of 1 over 1 plus energy over mp, c squared...