00:01
So in this problem, we have a 4 -mole gas, which is at the temperature of 400 kelvin.
00:06
It has been taken from volume v1 to v2, which is twice the original volume.
00:12
For the first problem, we want to find out the work done.
00:15
Remember that this process is isothermal, which means the temperature is constant.
00:20
Now, work is simply integral of pdv.
00:24
So that, in our case, because temperature is constant, we can use the state equation, pv is equal to n.
00:32
And see that pressure is nrt by b.
00:36
Because temperature is constant, this whole thing is a constant, and we have pressure as a function of volume.
00:43
So that's integral nrt dv by b.
00:46
Now, nrt is just a constant, so we can pull it out.
00:50
And because integral of 1 by v is log v, this turns out to be log v2 by v1.
00:56
And that is it.
00:58
This is our work.
00:59
We'll substitute our values.
01:01
N is 4 moles...