00:01
Hi, in the given problem there are x -axis and y -axis.
00:10
This is x -axis horizontal and this is y -axis vertical.
00:16
Now there is a charge particle cube whose position is x -0 meter and y also zero meter.
00:28
Means this is put at the origin a.
00:31
Then another charged particle having same magnitude cube, and that is put at a position having x is equal to 8 .0 meter and y is equal to 0.
00:43
So this is the position at the x -axis.
00:46
So this distance, oa, will be 8 .0 meter.
00:52
Then there is another point b.
00:58
There is another point c whose coordinates are 4 .0 meter comma 3 .0 meter means along x axis its distance is 4 .0 meter and along y axis this is 3 .0 meter then one more point b having coordinates x is equal to 4 .0 meter y is equal to 0.
01:34
So, definitely this is the point p lying at the middle of this line of this line of a like this.
01:43
Now, we have to find a charge, let it be capital q, put, which should be put at point b, which should make the net electric field at point c to be equal to zero.
01:57
So suppose the charge to be put at b.
02:10
In order to make the net electric field at c to be 0 is capital q, which we have to find.
02:32
This is unknown.
02:33
So first of all, we find net electric field at c because of only these two charges, small q each, for which we will have to join these distances, o, c and ac.
02:46
And using the symmetry, we conclude the two distances are same.
02:50
O .c.
02:52
Is equal to ac, which actually equal to hypotenuse.
02:55
So it will be given by pythagoros theorem.
02:58
4 square plus 3 square.
03:00
So this distance will come out to be 16 plus 9 means square root of 25 meter means this is 5 meter...