Comparing the entries of these two matrices, we get $a=a$, $0=b$, $c=c$, and $0=0$. Thus, $b=0$.
Now, let's compute the products $AB_2$ and $B_2A$:
$$
AB_2 = \left[\begin{array}{ll}
a & b \\
c & d
\end{array}\right] \left[\begin{array}{ll}
0 & 1 \\
0 &
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