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Problem 13 Easy Difficulty

Suppose a deuterium-deuterium fusion reactor is designed to have a plasma confinement time of 1.50 s. Determine the minimum ion density per cubic cm required to obtain a net power output from the reactor.

Answer

$6.67 \times 10^{15} \mathrm{cm}^{-3}$

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Top Physics 103 Educators
Marshall S.

University of Washington

Zachary M.

Hope College

Aspen F.

University of Sheffield

Meghan M.

McMaster University

Video Transcript

It's for this question. Where is she looking at the losses criteria for a nuclear fusion reactor to actually produce in output in the power rights. Rather then you know a net input. You have her net output off energy, and that is what Actually, it's a criteria for a functioning nuclear reactor. So for the losses criteria, it's stay steady. I own DST multiplied by the confinement. Time must be in more than tend to the pole off 16 in terms off the units, seconds and per centimeter. So what we want is to find what is. So I on the steed, as required, given that confinement time is 1.5 seconds. So basically, we just need to saw off by bringing the confinement time to D right. And this gives us 6.67 times tent pole 15 in terms off per centimeter. So this is the ion density required in the units posted a video acute

National University of Singapore
Top Physics 103 Educators
Marshall S.

University of Washington

Zachary M.

Hope College

Aspen F.

University of Sheffield

Meghan M.

McMaster University