Question
Suppose a neutron star with a radius of $10^{4} \mathrm{km}$ is spinning with a period of 0.001 sec. How fast is its equator moving? Compare this speed to the neutron star's escape velocity calculated in problem 1.
Step 1
The formula for the circumference of a circle is C = 2πr, where r is the radius. In this case, the radius of the neutron star is 10^4 km. C = 2π(10^4 km) ≈ 6.28 × 10^4 km Show more…
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