Question
Suppose a reaction has a negative $\Delta H^{\circ}$ and a negative $\Delta S^{\circ} .$ Will more or less product be present at equilibrium as the temperature is raised?
Step 1
Step 1: We start by referring to the Gibbs free energy equation, which is given by: \[\Delta G^{\circ} = \Delta H^{\circ} - T\Delta S^{\circ}\] Show more…
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The equilibrium constant for a reaction decreases as temperature increases. Explain how this observation is used to determine the sign of either $\Delta H^{\circ}$ or $\Delta S^{\circ}$.
(A): The equilibrium constant for a reaction having positive $\Delta H^{\circ}$ increases with increase of temperature. (R): The temperature dependence of the equilibrium constant is related to $\Delta \mathrm{H}^{\circ}$ and not $\Delta \mathrm{H}^{\circ}$ for the reaction.
If a reaction could exist that has $\Delta H=0$ what effect would temperature have on this reaction at equilibrium?
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