Question
Suppose $\cos \theta=u$ in $^{0<\theta<\frac{\pi}{2}}$ . Then $\tan \theta=$(A) 1(B) $\frac{1}{\sqrt{1-u^{2}}}$(C) $\frac{u}{\sqrt{1-u^{2}}}$(D) $\sqrt{1-u^{2}}$(E) $\frac{\sqrt{1-u^{2}}}{u}$
Step 1
We can draw a right triangle with angle $\theta$ such that the adjacent side is $u$ and the hypotenuse is $1$. This is because $\cos \theta$ is defined as the ratio of the adjacent side to the hypotenuse in a right triangle. Show more…
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