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Suppose David puts a $0.50-\mathrm{kg}$ rock into a sling of length 1.5 $\mathrm{m}$ and begins whirling the rock in a nearly horizontal circle, accelerating it from rest to a rate of 85 $\mathrm{rpm}$ after 5.0 $\mathrm{s}$ . What is the torque required to achieve this feat, and where does the torque come from?

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2.0 $\mathrm{m.N}$

Physics 101 Mechanics

Chapter 10

Rotational Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

University of Washington

Simon Fraser University

Hope College

University of Winnipeg

Lectures

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

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gonna treat the mass as a point point mass. And we can say that the torque required toe world the rock would be equaling the moment of inertia times the angular acceleration. This would be M r squared. And then, uh due to the definition of the angular acceleration, this would be the final angular velocity minus the initial angular velocity. We know the initial angular velocity zero, and then this would be divided by t. So this is equaling. We can say the torque needed would be point 50 kilograms multiplied by 1.5 meters, quantity squared, divided by 5.0 seconds. We're gonna multiply this by 85 revolutions per minute. This would be multiplied by to pyre a Deion's for every revolution on, then multiplied by one minute for every 60 seconds. And this is equal in approximately 2.0 Newton meters. This would be the torque needed to world Iraq. 2.0 Newton meters would be our final answer. That is the end of the solution. Thank you. For what

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