Question
Suppose $f$ and $g$ are functions that are differentiable at $x=1$ and that $f(1)=2, f^{\prime}(1)=-1, g(1)=-2,$ and $g^{\prime}(1)=3 .$ Find the value of $h^{\prime}(1)$.$$h(x)=\left(x^{2}+1\right) g(x)$$
Step 1
We can use the product rule for differentiation which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function. Show more…
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Suppose $f$ and $g$ are functions that are differentiable at $x=1$ and that $f(1)=2, f^{\prime}(1)=-1, g(1)=-2,$ and $g^{\prime}(1)=3 .$ Find the value of $h^{\prime}(1)$. $$h(x)=f(x) g(x)$$
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Suppose $f$ and $g$ are functions that are differentiable at $x=1$ and that $f(1)=2, f^{\prime}(1)=-1, g(1)=-2,$ and $g^{\prime}(1)=3 .$ Find the value of $h^{\prime}(1)$. $$h(x)=\frac{x f(x)}{x+g(x)}$$
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