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Suppose $f(x)=\left\{\begin{array}{ll}a+b x, & x<1 \\ 4, & x=1 \\ b-a x, & x>1\end{array}\right.$and if $\lim _{x \rightarrow 1} f(x)=f(1)$ what are possible values of $a$ and $b$ ?
a=0, b=4
Calculus 1 / AB
Chapter 13
Limits and Derivatives
Section 1
Introduction
Limits
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in this problem we have limited extends to one. Fx equals two. Effect one which is nothing but four. You see that limit effects exist, which means that limit X approaching from the left hand side of one, which is the left hand side of the limit. Fx should also be four. This is equals two. Limit Extends to one X must be mhm Sign this is A plus B X. This is equal to four. It means that A plus B sequester from also The right hand side of the limit should also be equal to four. The fx title chooses b minus X. So this is nothing right b minus A. And this should also be equal to four. So we have two week visions Equation one and equation too. Let us add these equations so one plus two we get to be equals two. It or Knech equals to four. This means that is Christian zero. So this foreign is it not
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