Question
Suppose $\int_{0}^{3} f(x) d x=2, \int_{3}^{6} f(x) d x=-5$ and $\int_{3}^{6} g(x) d x=1 .$ Evaluate the following integrals.a. $\int_{0}^{3} 5 f(x) d x \quad$ b. $\int_{3}^{6}(-3 g(x)) d x$c. $\int_{3}^{6}(3 f(x)-g(x)) d $ d. $\int_{6}^{3}(f(x)+2 g(x)) d x$
Step 1
Since 5 is a constant, we can pull it out of the integral to get $5 \int_{0}^{3} f(x) d x$. We know that $\int_{0}^{3} f(x) d x = 2$, so the result is $5 \times 2 = 10$. Show more…
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