00:01
The topic of this question is going to be eigenvalues and eigenvectors.
00:08
So this question asks us to prove that if we have a matrix a that is invertible and has an eigenvalue lambda corresponding to eigenvector x, then the inverse of a will have an eigenvalue lambda also corresponding to an eigenvector x, the same vector x.
00:40
So this is what we have, and this is what we want to show.
00:46
So given this and all the other information we have, which is that a is invertible, how do we end up with this, or something that tells us this? well, since we want to get a inverse x somehow, we can start by multiplying the left side of both sides of our equation by a inverse.
01:17
Multiplying both sides of the equation on the left side by any inverse.
01:23
There isn't a very nice way of saying that.
01:27
But we have to be careful about which side we do it on, because which way we arrange matrices matters.
01:37
It might change in the multiplication.
01:41
So notice that a inverse a gives us i, the identity matrix, and notice that since we have a scalar here, and a scalar multiplied by a vector, all multiplied by a matrix, is the same thing as a scalar multiplied by the matrix vector product...