Suppose $q(\mathbf{x})=\mathbf{x}^T A \mathbf{x}=\sum_{i, j=1}^n a_{i j} x_i x_j$ is a general quadratic form on $\mathbb{R}^n$, whose coefficient matrix $A$ is not necessarily symmetric. Prove that $q(\mathbf{x})=\mathbf{x}^T K \mathbf{x}$, where $K=\frac{1}{2}\left(A+A^T\right)$ is a symmetric matrix. Therefore, we do not lose any generality by restricting our discussion to quadratic forms that are constructed from symmetric matrices.