Suppose that $\$ 100$ is deposited into an account earning interest at $6 \% /$ year compounded monthly. Let $a_{n}$ denote the amount on deposit (called the accumulated amount or the future value) at the end of the $n$ th month.
a. Show that $a_{1}=100(1.005), a_{2}=100(1.005)^{2},$ and $a_{3}=100(1.005)^{3}$ b. Find the accumulated amount $a_{n}$ c. Find the 24 th term of the sequence $\left\{a_{n}\right\}$, and interpret your result.