00:01
So guys, in this problem, we need to find the displacement of a particle given the velocity function, t -square minus 3d minus 18, and we also need to find the total distance traveled by this particle given the time period from 0 to 6 seconds.
00:18
So in order to determine the total distance, we must take note the change in direction of the velocity to particle.
00:26
We can take note of that by solving it to zeros.
00:31
So we'll import the 0 of velocity function, we will have t squared minus 3t minus 18 equals 0.
00:42
And we can factor this to t minus 6 times t plus 3 equal to 0.
00:53
And we will get t is equal to negative 3 and 6.
01:02
So by this one, we can see that the particle will have a change in direction at time negative 3.
01:11
And at times six.
01:15
As we can see in graph here.
01:20
But we just need to know the distance between this time period.
01:25
So this is just a single setup for the integral...