Here, $a = 1$, $b = 2$, and $c = -8$. So, the x-coordinate of the vertex is $-\frac{b}{2a} = -\frac{2}{2} = -1$. Substituting $x = -1$ into the function gives the y-coordinate of the vertex as $f(-1) = (-1)^2 + 2(-1) - 8 = -9$. So, the vertex of the function is
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