Question
Suppose that $p(x)=\frac{1}{5}, x=1,2,3,4,5$, zero elsewhere, is the pmf of the discrete-type random variable $X$. Compute $E(X)$ and $E\left(X^{2}\right)$. Use these two results to find $E\left[(X+2)^{2}\right]$ by writing $(X+2)^{2}=X^{2}+4 X+4$.
Step 1
The expectation of a discrete random variable is given by the formula $E(X) = \sum_{i} x_{i}p(x_{i})$, where $x_{i}$ are the possible values of the random variable and $p(x_{i})$ are their corresponding probabilities. In this case, $p(x_{i}) = \frac{1}{5}$ for Show more…
Show all steps
Your feedback will help us improve your experience
Sagar Singh and 75 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A discrete probability distribution for a random variable $\bar{X}$ is given. Use the given distribution to find $(a)$ $P(X \geq 2)$ and $(b) E(X)$. $$p_{i}=(5-i) / 10, x_{i}=i, i=1,2,3,4$$
Applications of the Integral
Probability and Random Variables
Let $p_{X}(x)=x / 15, x=1,2,3,4,5$, zero elsewhere, be the pmf of $X$. Find $P(X=1$ or 2$), P\left(\frac{1}{2}<X<\frac{5}{2}\right)$, and $P(1 \leq X \leq 2)$.
Probability and Distributions
Random Variables
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD