00:01
This video we are asked to determine whether the following combination of these two equivalent relations are also equivalent relation.
00:15
So we only know that these two are some equivalent relation on the set s, on the same set.
00:23
And this statement is very general, so it's for any set as, any set as, any, equivalent relation are 1 and r2 so there are two choice or two scenario that can happen either the combination we are looking at is equivalent relation in which case we have to prove the three conditions of equivalent relation right and another scenario is that is not an equivalent relation in that in this case we only need one counter example to to justify saying that is not true all right so in those cases i will give counter example which mean we can i can decide on what kind of set s is and what relation are one and are two are okay so let's go so you you see the can't return on the board you you probably know that it's not yes this one is not equivalent relation why so i have this scenario where suppose s has three elements abc r1 and r2 are equivalent relations you have everything related to itself so we have reflexive symmetry because if ab is in there, b is in there.
02:20
And transitivity, but we don't have to really check that because we create it in such a way that it doesn't concern three things at once.
02:31
So there is no ac or something like that.
02:36
But the main thing to consider is that when we union them, now inside, inside, inside this union we have ab and b c, right? and so transitivity would imply that we must have ac as well for this thing to be, this union to be equivalent relation.
03:06
But no, we don't have this element because it's not in any like equivalent relation that we're starting with.
03:19
So this one is not.
03:24
This is one counter example...