00:01
I'm going to look at today refers to the offspring containing the ability to taste phenothelicarbonide, which i'm going to abbreviate as ptc.
00:09
So as you can see, we're going to fill out out punnett square today.
00:14
So in order for an offspring to taste ptc, it has to have a dominant gene, which we will represent as capital t.
00:23
And people unable to taste ptc has to have a homozygous recessive gene, which we will represent as lowercase t.
00:33
So before before we get started, let's define homozygous recessive gene.
00:38
When you have a recessive allele and another recessive allele, that's when you have a homozygous recessive gene.
00:49
So remember that the prefix homo means the same, so they both contain the same allele.
00:58
And for the homozygous dominant gene, instead of being recessive, two recessive, it's two dominant alleles.
01:05
For the heterozygous dominant gene, or just heterozygous gene, you'll have one dominant gene or allele and one recessive allele.
01:17
So let's go to the first question.
01:20
If we have two heterozygous parents and three offspring, what will the proportion be of tasters and non -tasters? so if we have two heterozygous parents, we'll have a dominant allele and a recessive allele.
01:35
Since they're both heterozyas, i guess, be the exact same.
01:40
So in order to fill out pundit square, you simply fill it out by going over and just going down.
01:53
So dominant allele and a dominant allele.
01:56
And you'll do that for the next one as well.
02:02
Oops.
02:08
So then you'll go over to the next one and do a dominant allele, a recessive allele, and then you go to the next one.
02:24
I like writing my recessive genes or alleles to the right.
02:30
And the dominant ones to the left and do that and that's how you filled them out.
02:42
So now i want to make it look cleaner so i'll just fill it up quickly.
02:54
So again you just go down into the right and so now we have, now we're able to find our proportions.
03:07
So let's count how many dominant genes we have.
03:10
We have one, two, three.
03:13
So three out of four, because there's four, four squares.
03:17
One, two, three, four squares.
03:20
That gives us 75%.
03:25
And we have one recessive, one homozygous recessive, which is the inheritance of unable to taste ptc.
03:47
Over 4 equals 25%, and that is our proportion for this opponent square.
03:56
So we also want, so the next question is, what are the likelihoodness of all three offspring being tasters or non -tasters? so by this we're going to be using fractions.
04:11
So let me clear this right here.
04:21
So we have our two heterozygous parents still.
04:28
The question is still referring to the heterozygous parents...