00:01
So from our question, we know the domain of the propositional function, which is p of x, consists of negative 5, negative 3, negative 1, 3, and positive 5.
00:20
So now we are going to write the proposition using the disjunction, conjunctions, and negations.
00:27
So the conjunction of p and k is denoted by p conjunction q.
00:38
So the conjunction is true when both p and k are true and is false otherwise.
00:47
Also the disjunction of p and kiel is denoted by p this junction.
00:56
This junction is false when both p and kill are false and is true.
01:02
In remaining conditions.
01:05
The negation of p and kof is denoted by, sorry, the negation of p is denoted by this.
01:15
So this is the denotion.
01:18
This is the notation, sorry.
01:21
The true value of the negation of p is the opposite of the true of p.
01:28
So now we can move on to the part a and start solving...