Question
Suppose that the total magnetic moment per cubic metre in a spinel structure in which $\mathrm{Ni}^2$ iorts have replaced a portion of the $\mathrm{Fe}^{2+}$ ion is $4.6 \times 10^5 \mathrm{~A} . \mathrm{m}^{-1}$. Calculate the fraction of the $\mathrm{Fe}^{2+}$ lons that have been replaced and the wt\% Ni present in the spinel.
Step 1
The magnetic moment per ion for $\mathrm{Fe}^{2+}$ is approximately $4.9 \times 10^{-24} \mathrm{~A} \cdot \mathrm{m}^2$, and for $\mathrm{Ni}^{2+}$, it is approximately $2.9 \times 10^{-24} \mathrm{~A} \cdot \mathrm{m}^2$. Show more…
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