Question
Suppose that the velocity of a parachutist is $$v(t)=65\left(1-e^{-0.16 t}\right)$$meters per second. The graph of $v(t)$ is similar to that in Fig. 2 Calculate the parachutist's velocity and acceleration when $t=9$ seconds.
Step 1
We can do this by substituting $t=9$ into the given velocity function $v(t)=65\left(1-e^{-0.16 t}\right)$. So, $v(9)=65\left(1-e^{-0.16 \times 9}\right)$. Show more…
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Suppose that the velocity of a parachutist is $$v(t)=65\left(1-e^{-.16 t}\right)$$ meters per second. The graph of $v(t)$ is similar to that in Fig. 3. Calculate the parachutist's velocity and acceleration when $t=9$ seconds.
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The velocity of a parachutist during free fall is $$f(t)=60\left(1-e^{-0.17 t}\right)$$ meters per second. Answer the following questions by reading the graph in Fig. 2. (Recall that acceleration is the derivative of velocity.) (a) What is the velocity when $t=8$ seconds? (b) What is the acceleration when $t=0 ?$ (c) When is the parachutist's velocity $30 \mathrm{m} / \mathrm{sec} ?$ (d) When is the acceleration $5 \mathrm{m} / \mathrm{sec}^{2} ?$
The velocity of a parachutist during free fall is $$f(t)=60\left(1-e^{-.17 t}\right)$$ meters per second. Answer the following questions by reading the graph in Fig. 3. (Recall that acceleration is the derivative of velocity.) (a) What is the velocity when $t=8$ seconds? (b) What is the acceleration when $t=0 ?$ (c) When is the parachutist's velocity $30 \mathrm{~m} / \mathrm{sec}$ ? (d) When is the acceleration $5 \mathrm{~m} / \mathrm{sec}^{2} ?$
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