Suppose that we seek an intuitive estimator for $$\rho=\frac{\operatorname{Cov}(X, Y)}{\sigma_{X} \sigma_{Y}}$$ a. The method-of-moments estimator of $\operatorname{Cov}(X, Y)=E\left[\left(X-\mu_{X}\right)\left(Y-\mu_{Y}\right)\right]$ is $$\operatorname{Cov} \widehat{(X, Y)}=\frac{1}{n} \sum_{i=1}^{n}\left(X_{i}-\bar{X}\right)\left(Y_{i}-\bar{Y}\right)$$ Show that the method-of-moments estimators for the standard deviations of $X$ and $Y$ are $$\partial_{X}=\sqrt{\frac{1}{n} \sum_{i=1}^{n}\left(X_{i}-\bar{X}\right)^{2}} \text { and } \partial_{Y}=\sqrt{\frac{1}{n} \sum_{i=1}^{n}\left(Y_{i}-\bar{Y}\right)^{2}}$$ b. Substitute the estimators for their respective parameters in the definition of $\rho$ and obtain the method-of-moments estimator for $\rho .$ Compare your estimator to $r$, the maximum-likelihood estimator for $\rho$ presented in this section.