00:01
Here we have x, a binomial random variable with n equals 200 and p equals 0 .4.
00:09
And we are asked to approximate some probabilities for x.
00:13
Now we can use the normal approximation to the binomial if n times p is greater than 5.
00:23
And if n times 1 minus p is also greater than 5.
00:30
So here we have n times p is equal to 80, and n times 1 minus p is equal to 120.
00:48
Both are significantly bigger than 5, which suggests that we can use the normal approximation as a good approximation.
01:05
For a, we are looking for the probability that x is less than or equal to 70.
01:16
And since we're going to use the normal approximation, we want to include the continuity correction factor.
01:27
That is looking for the probability that x is less than or equal to 70 .5.
01:33
And this is going to be approximately equal using the approximation to the probability that z is less than or equal to 70 .5 minus n times p over the square root of n times p times 1 minus p.
02:06
This is the probability that z is less than or equal to 70 .5 minus 80, which we've already solved for here, divided by 80 times 0 .6.
02:27
This is all square root of.
02:34
It's equal to the probability that z is less than or equal to negative 1 .3712, and this is equal to approximately 0 .08 5 -2.
02:56
For part b we want the probability that x is greater than 70 and less than 90.
03:14
Now this is equal to the probability that x is less than 90 minus the probability that x is less than or equal to 70.
03:30
Now i'm making sure to get this less than or equal correct because it matters when we apply the continuity correction factor...