Suppose that $Y$ is normally distributed with mean 0 and unknown variance $\sigma^{2} .$ Then $Y^{2} / \sigma^{2}$ has a $x^{2}$ distribution with 1 df. Use the pivotal quantity $Y^{2} / \sigma^{2}$ to find a a. $95 \%$ confidence interval for $\sigma^{2}$ b. $95 \%$ upper confidence limit for $\sigma^{2}$. c. $95 \%$ lower confidence limit for $\sigma^{2}$.