The equivalent capacitance of this series combination is given by the formula for capacitors in series:
\[
\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2}
\]
Substituting the given values, we get:
\[
\frac{1}{C_{eq}} = \frac{1}{12} + \frac{1}{6}
\]
Solving this
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