Question
Suppose the gravitational force varies inversely as the nth power of distance the time period of planet in circular orbit of radius $\mathrm{R}$ around the sun will be proportional to(A) $\mathrm{R}^{[(\mathrm{n}+1) / 2]}$(B) $\mathrm{R}^{[(\mathrm{n}-1) / 2]}$(C) $\mathrm{R}^{\mathrm{n}}$(D) $\mathrm{R}^{[(\mathrm{n}-1) / 2]}$
Step 1
The gravitational force acting on the planet is given by $F = G \frac{Mm}{R^n}$, where $G$ is the gravitational constant, $M$ is the mass of the sun, $m$ is the mass of the planet, and $R$ is the distance between the sun and the planet. Show more…
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Suppose the gravitational force varies inversely as the nth power of distance the time period of planet in circular orbit of radius R around the sun will be proportional to (A) R^[(n+1) / 2] (B) R^[(n – 1)/2] (C) R^n (D) R^[(n – 1)/2]
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Suppose the gravitational force varies inversely as the $n^{\text {th }}$ power of the distance. Then the time period of a planet in circular orbit of radius $R$ around the sun will be proportional to : (a) $R^{n}$ (b) $R^{(n+1) / 2}$ (c) $R^{(n-1) / 2}$ (d) $R^{-n}$
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