00:01
The given problem here, this is the xx, this is the y -axis, and perpendicular to both of these.
00:24
This is the x -axis.
00:30
Then there is a rectangular coil which has been kept in such a manner that two or two or a its sides are parallel to y -axis and other two sides are parallel to the x -axis and x -axis is perpendicular the plane of this soil then magnetic field is along the x -axis here this is the magnetic field.
01:20
Area of the loop is given as a is equal to 600 centimeter square or we can say this is a 600 into 10 dash bar minus 4 meter square angular velocity of the rotation of the coil is given as 35 .10 radiant per second and this magnet which is along the x -axis is given as 0 .3 to 0 as law.
02:04
In the first part of the problem it is said that the coil, the loop is rotating about y -axis is here like this.
02:29
So then the loop will be rotating about y -axis flux linked through this loop will be given by b .a or we can say this is b a cost theta theta with the angle between the area vector and magnetic field and as the angular speed of this rotation is omega so at any instant t this angular displacement theta will be given as distance equals to speed into time.
03:08
So angular distance equals to angular speed into time means omega t.
03:14
So the emf induced across this coil will be given as minus d5 by dt as per faraday's laws of electromagnetic induction.
03:29
So it will be given as d by dt means differentiation of b8 cost omega t.
03:38
Here, b into a, it means as it is being constant, then differentiation of cosine will be minus sine omega -t, and then differentiation of omega -t with respect to time, that will give us omega.
03:54
So finally, it comes out to be omega into a into b, into sine omega -t.
04:03
And then for maximum emf induced, the sign should have a maximum value which is just one.
04:21
Therefore, this maximum emf induced will be given by omega into a into b.
04:30
So for omega, this is 35 radian per second...